please answer my question urgently properly
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let the maximum marks =x
pass mark = t
given
36* x/100 = y - 24
and 43 * x/100 = y + 18
simplying it we get,
y = 0.36x +24
and y = 0.43x -18
puting value of y in second equation
0.36 x + 24 = 0.43 x -18
x = 600
now putting value of x in any eq we get
y = 0.36*600 +24= 240
percentage of pass marks = 240/600 = 0.4 = 40%
and maximum marks is 600 ...pls mark it branliest if it helped u.
pass mark = t
given
36* x/100 = y - 24
and 43 * x/100 = y + 18
simplying it we get,
y = 0.36x +24
and y = 0.43x -18
puting value of y in second equation
0.36 x + 24 = 0.43 x -18
x = 600
now putting value of x in any eq we get
y = 0.36*600 +24= 240
percentage of pass marks = 240/600 = 0.4 = 40%
and maximum marks is 600 ...pls mark it branliest if it helped u.
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