please answer
please find the x
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ANSWER :
The ∆ABD is an isosceles triangle
Because
AD = BD
We know that
Isosceles triangle : The triangle with two equal sides and sides opposite angles are also equal.
So, now
angle BAD = angle DBA
angle BAD = 29°
Using angle sum property
angle BAD + angle DBA + angle ADB = 180°
29° + 29° + angle ADB = 180°
angle ADB = 180° - 58°
angle ADB = 122°
We know that
Exterior angle = sum of interior opposite angles
Here , exterior angle = angle ADC
angle ADC = angle DAB + angle DBA
angle ADC = 29° + 29°
angle ADC = 58°
Taking ∆ADC
It is an isosceles triangle
Because,
AD = DC
angle CAD = angle DCA
TO FIND :
angle x
angle x = angle DCA
Using angle sum property
angle CAD + angle DCA + angle ADC = 180°
x° + x° + 58° = 180°
2x° = 180° - 58°
2x° = 122°
x° = 61°
Hence x = 61
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