Question

Please answer question number 35.

Answer 1

Heya

Two linear equations will have infinite solutions when

a1/a2 = b1/b2 = c1/c2

2/p+q = 3/2p-q

4p-2q = 3p+3q

4p-2q-3p-3q = 0

p-5q = 0.....(1)

2/p+q = 9 / 3(p+q+1)

2(p+q+1) = 3(p+q)

2p+2q+2-3p-3q = 0

-p -q = -2.......(2)

(1)+(2)

p - 5q = 0
-p-q = -2

=> -6q = -2

q = 1/3

Substituting q= 1/3 in (1)

p -5(1/3) = 0

p = 5/3

Hope it helps ^_^