Question

Please answer

solve for x

1/(x-3)+2/(x-2)=8/x; x not equal to 0,2,3

Answer 1

Quadritatic Equations,

We have,

$\frac{1}{x - 3} + \frac{2}{x - 2} = \frac{8}{x}$
Where x not equal to 0,2 and 3
Have to find the value of x

Now,$\frac{1}{x - 3} + \frac{2}{x - 2} = \frac{8}{x} \\ or, \frac{x - 2 + 2x - 6}{(x - 3)(x - 2)} = \frac{8}{x} \\ or,\frac{3x - 8}{ {x}^{2} - 5x + 6 } = \frac{8}{x} \\ or,3 {x}^{2} - 8x = 8 {x}^{2} - 40x + 48 \: \: \: (by \: cross \: multiplicarion) \\ or, 5 {x}^{2} - 32x + 48 = 0 \\ or, 5 {x}^{2} - 12x - 20x + 48 = 0 \\ or, x(5x - 12) - 4(5x - 12) \\ or, (5x - 12)(x - 4) = 0 \\ so \: x \: = \frac{12}{5} \: , \: 4$

That's it
Hope it helped (≧▽≦)

Answer 2

Step-by-step explanation:

answer is 12/5 and 4