Question

please answer the question​

Answer 1

Answer:

a=0

b=7/11

Step-by-step explanation:

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Answer 2

Answer:

GIVES THAT :–

$= > \frac{7 + \sqrt{5} }{7 - \sqrt{5} } - \frac{7 - \sqrt{5} }{7 + \sqrt{5} } = a + b \sqrt{5} \\ \\ = > \frac{ {(7 + \sqrt{5}) }^{2} - {(7 - \sqrt{5} )}^{2} }{(7 + \sqrt{5})(7 - \sqrt{5} ) } = a + b \sqrt{5} \\ \\ = > \frac{49 + 5 + 14 \sqrt{5} - (49 + 5 - 14 \sqrt{5} )}{(49 - 5)} = a + b\sqrt{5} \\ \\ = > \frac{28 \sqrt{5} }{44} = a + b \sqrt{5} \\ \\ = > \frac{7 \sqrt{5} }{11} = a + b \sqrt{5}$

SO ,

$a = 0$

$b = \frac{7}{11}$

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