Question

please answer the question

Answer 1

Hello User !!!

Area of the trapezium = 686 cm²

Height = 28 cm

Let one parallel side be 'x'

and other parallel side will be ( x + 7 )

Formula to find area of a trapezium :

Area = ½ × Sum of parallel sides × h

686 = ½ × [ x + ( x + 7 ) ] × 28

686 = ( 2x + 7 ) × 14

686/14 = 2x + 7

49 = 2x + 7

2x = 42

x = 21

x + 7 = 28

So the parallel sides are 21 cm and 28 cm

Answer 2

Area of trapezium=686cm^2
Height(h)=28cm
Let bigger(or base) side(b) =x cm
So, smaller(or upper) side(a)=(x-7)cm
A/Q,
$area = 686cm {}^{2} \\ \frac{1}{2} (a + b)h = 686cm {}^{2} \\ \frac{1}{2}(x + x - 7)28 = 686 \\ 2x - 7 = \frac{686 \times 2}{28} \\ 2x - 7 = 49 \\ 2x = 49 + 7 \\ 2x = 56 \\ x = \frac{56}{2} \\ x = 28$

So,Larger parallel side=x=28cm
Smaller parallel side=x-7=28-7=21cm.