please answer the question
Attachments:
Answers
Answered by
0
let the number of sides be x.
10 right angle=90*10=900 degree.
let each angle be n.
ATQ:
900/x=n
BUT x=n(number of side=number of angles)
so,
900/x=x
x^2=900
x=30 degree.
number of sides =30
done.:-)
10 right angle=90*10=900 degree.
let each angle be n.
ATQ:
900/x=n
BUT x=n(number of side=number of angles)
so,
900/x=x
x^2=900
x=30 degree.
number of sides =30
done.:-)
chopraneetu:
i don't think it is right
Answered by
0
sum of all angles of a polygon with n sides=(n-2)×180
here sum is 10 right angles=10×90
(n-2)180=10×90
(n-2)180=900
here sum is 10 right angles=10×90
(n-2)180=10×90
(n-2)180=900
Similar questions
Math,
8 months ago
Science,
8 months ago
Chemistry,
1 year ago
Math,
1 year ago
Psychology,
1 year ago