Math, asked by raj51772, 1 year ago

please answer the question

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Answered by helpingbuddy40
0
let the number of sides be x.

10 right angle=90*10=900 degree.

let each angle be n.

ATQ:
900/x=n

BUT x=n(number of side=number of angles)

so,

900/x=x
x^2=900
x=30 degree.

number of sides =30

done.:-)



chopraneetu: i don't think it is right
raj51772: yes this wrong
helpingbuddy40: maybe idk.
helpingbuddy40: sorry
raj51772: ok don't worry I got the ans
helpingbuddy40: nice
Answered by chopraneetu
0
sum of all angles of a polygon with n sides=(n-2)×180
here sum is 10 right angles=10×90
(n-2)180=10×90
(n-2)180=900
n - 2 = \frac{900}{180} \\ n - 2 = 5 \\ n = 7

chopraneetu: i don't know y leomanish has deleted my answer
chopraneetu: what's wrong in this
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