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Hi!
Here is the answer to your question.
The given equation is Acos2θ + B cos2θ + C = 0
Acos2θ + Bcos2θ + C = 0
⇒ A (2cos2θ – 1) + Bcos2θ + C = 0
⇒ (2A + B) cos2θ + (C – A) = 0 (1)
Since, equation (1) is satisfied for all θ,
∴ 2A + B = 0 and C – A = 0 ( cos2θ ε [0, 1])
⇒ B = –2A and A = C
There are infinite may solutions which satisfied the equations A = C and B = –2A.
Hence, there are infinite solutions of the triplet (A, B, C).
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refer the attchment
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