Question

Please answer these questions asap​

Answer 1

Answer:

6)1,-4

7) 1,3

8) -2

Step-by-step explanation

6)keep X^3 -  13  X+12 =0

then resolve this into (x-1)(x-3)(x+4)

the roots will be 1 ,3 ,-4  

7) same as the above sum keep the equation equal to zero

then resolve this into (X-3)(X-1)(X+1)=0

the roots will be 1,-1,4

8) let the roots of equation be p,q,r

we know s3=pqr=6/3=2

but given pq=-1

so -r=2

therefore r=-2