Question

Please answer third one.

Answer 1

Hi Friends ✋✋

I hope your question is

(iii) x² + 6x -10

If it is by quadratic formula then :-

x = [-b ± √( b² - 4ac)]/2a

here a = 1
b = 6
and c = -10

therefore

x = -6 ± √ (36 + 40)/2

x =[ -6 ± √76]/2

x = [-6 ± 2√19]/2

x = -3 ± √19

hope it helps

Answer 2

Heya user,

Your Question ---> x² + 6x - 10 = 0

Soln. -->

---> x² + 6x - 10 = 0
=> x² + 6x + 9 - 9 - 10 = 0 
=> [ x + 3 ]² - 19 = 0
=> [ x + 3 ]² = 19
=> [ x + 3 ] = + √19 or - √19
=> x = [ - 3 - √19 ]     or     [ √19 - 3 ]

Hope this is easy and it helps....