Please answer third one.
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Answered by
2
Hi Friends ✋✋
I hope your question is
(iii) x² + 6x -10
If it is by quadratic formula then :-
x = [-b ± √( b² - 4ac)]/2a
here a = 1
b = 6
and c = -10
therefore
x = -6 ± √ (36 + 40)/2
x =[ -6 ± √76]/2
x = [-6 ± 2√19]/2
x = -3 ± √19
hope it helps
I hope your question is
(iii) x² + 6x -10
If it is by quadratic formula then :-
x = [-b ± √( b² - 4ac)]/2a
here a = 1
b = 6
and c = -10
therefore
x = -6 ± √ (36 + 40)/2
x =[ -6 ± √76]/2
x = [-6 ± 2√19]/2
x = -3 ± √19
hope it helps
BrainlyHulk:
i had done mind calculation
Kk. Can you edit the answer
i had
eddited
Plz do it soon
i had done
But no changes
hmm just check it
or refresh
thanks for marking as brainliest
Answered by
1
Heya user,
Your Question ---> x² + 6x - 10 = 0
Soln. -->
---> x² + 6x - 10 = 0
=> x² + 6x + 9 - 9 - 10 = 0
=> [ x + 3 ]² - 19 = 0
=> [ x + 3 ]² = 19
=> [ x + 3 ] = + √19 or - √19
=> x = [ - 3 - √19 ] or [ √19 - 3 ]
Hope this is easy and it helps....
Your Question ---> x² + 6x - 10 = 0
Soln. -->
---> x² + 6x - 10 = 0
=> x² + 6x + 9 - 9 - 10 = 0
=> [ x + 3 ]² - 19 = 0
=> [ x + 3 ]² = 19
=> [ x + 3 ] = + √19 or - √19
=> x = [ - 3 - √19 ] or [ √19 - 3 ]
Hope this is easy and it helps....
Hope you find it ---> helpful
Yeah. It's very helpful for me
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