Question

please answer this I will mark you as Brainliest
don't post irrelevant answers please I am losing my points asking questions so please answer if you know ​

Answer 1

Answer:

< AQD = 50°

< EDG = 90°

< DPF = 90°

Step-by-step explanation:

GIVEN:

<APF = 50

<CDG = 40

TO FIND :

<AQD=?

<EDG=?

<DPF=?

SOLUTION :

As DE||PF hence , EQ||PF

Thus, <APF= <AQD -----{ corresponding angles}

∴<AQD = 50°

Now, AB||CD hence ,<GDC = < DPB = 40°

As you see AB is a straight line ;

∴< APF + < DPF + < DPB = 180°

50°+ <DPF + < 40° = 180°

90° + < DPF = 180°

∴<DPF = 90°

Now < DPF = < EDG = 90° -----{ corresponding angles}

∴<EDG = 90°

HOPE IT HELPS YOU!

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