Math, asked by anas7152, 9 months ago

please answer this Q​

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Answered by Anonymous
1

Here we have 36y^2 - 64z^2 upon 6y - 4z.

Now we can write 36y^2 as (6y)^2 and 64z^2 as (8z)^2.

Therefore we get (6y)^2 - (8z)^2/6y - 4z.

Now using a^2 minus b^2 = (a + b)(a - b), we get

(6y + 8z)(6y - 8z)/ 6y - 4z

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