Question

please answer this question ​

Answer 1

Hope this helps. Thankyou

Answer 2

$LHS = \frac{3 - \sqrt{5}}{3+2\sqrt{5}}$

$= \frac{(3 - \sqrt{5})(3-2\sqrt{5})}{(3+2\sqrt{5})(3-2\sqrt{5})}$

$= \frac{3(3-2\sqrt{5})-\sqrt{5}(3-2\sqrt{5})}{3^{2} - (2\sqrt{5})^{2}}$

$= \frac{9-6\sqrt{5} - 3\sqrt{5} + 10}{9-20}$

$= \frac{19-9\sqrt{5}}{-11}$

$= \frac{-19}{11} + \frac{9\sqrt{5}}{11}$

$= \frac{9\sqrt{5}}{11} - \frac{19}{11} \: --(1)$

$RHS = a\sqrt{5} - b \: ---(2)$

/* Compare (1) and (2), we get */

$\green { a = \frac{9}{11} , \: b = \frac{19}{11} }$

•••♪