Question

please answer this question​

Answer 1

Step-by-step explanation:

0 < a < x.

| log x base a + log a base x |

⇒| log x base a +1 upon log x base a |

[ let log x base a = t ]

⇒| t + $\frac{1}{t}$ |

⇒2

{ ( a - 1)² is greater than or equal to 0⇒a² +1 -2a is greater than or equal to 0⇒a + 1/a is greater than or equal to 2 }

Hence,the sum of a number and its reciprocal is greater than or equal to 2

therefore,the minimum value of | log x base a + log a base x | is 2

$<marquee>Hope this helps you mate$