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BC=14cm
AB=1/2BC
=14/2 = 7cm
AE = 7+7 = 14cm
area of quad AEFD = 14×14 = 196 cm²
area of ∆ABC = 1/2× b×h = 1/2 × BC×AB
= 1/2 ×14×7 = 49 cm²
area of semicircle= 1/2 πr²
=1 ×22×7×7
2 7
=11×7 = 77cm²
area of shaded region = area of AEFD - (area of ∆ABC+ area of semicircle)
= 196 - (49+77)
= 196 - 126
= 70 cm²
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