Question

please answer this question

Answer 1

FC=EB

F= 90degree
E=90degree

B=C
A is the mid point of B,C

BF=CE

therefore,FC=EB

hope it helps.......

✌mark as brainliest....
✌be brainly....

Answer 2

HERE'S YOUR ANSWER
--------------------------------
In ∆ ABC
(A) angle F = angle E (90°)
(A) angle FBC = angle ECB (isosceles triangle)
(S) side BC is common
so by AAS criteria we have prove that ∆ FBC congruent to ∆ ECB
•Corresponding parts of congruent triangles are equal .
so, altitude FC = altitude EB

PLS MARK MY ANSWER AS BRAINLIEST