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icse
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Answered by
3
hey dear your answer is here..
=1-2tan+tan^2+1+2tan+tan^2
=2(1+tan^2)
=2sec^2
=1-2tan+tan^2+1+2tan+tan^2
=2(1+tan^2)
=2sec^2
Answered by
3
L. H. S.=
(1-tanA)^2 + (1+tanA)^2
1+tan^2A - 2tanA + 1 + tan^2A + 2tanA
Sec^2A + Sec^2A
= 2Sec^2A
Hence Proved.....!
(1-tanA)^2 + (1+tanA)^2
1+tan^2A - 2tanA + 1 + tan^2A + 2tanA
Sec^2A + Sec^2A
= 2Sec^2A
Hence Proved.....!
icse
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