Question

please answer this question

Answer 1

Answer:

Option(3)

Step-by-step explanation:

Let xᵃ = yᵇ = z^c = p.

(i)

xᵃ = p

x = p^(1/a)

(ii)

yᵇ = p

y = p^(1/b)

(iii)

z^c = p

z = p^(1/c)

Given that y² = zx

$=>(p^{\frac{1}{b})^2}=p^{\frac{1}{c}}*p^{\frac{1}{a}}$

$=>p^{\frac{2}{b}}=p^{\frac{1}{c}}*p^{\frac{1}{a}}$

$=>p^{\frac{2}{b}}=p^{\frac{1}{c}+\frac{1}{a}}$

$=>\boxed{\frac{2}{b}=\frac{1}{a}+\frac{1}{c}}$

Hope it helps!

Answer 2

Step-by-step explanation:

Let xᵃ = yᵇ = z^c = p.

(i)

xᵃ = p

x = p^(1/a)

(ii)

yᵇ = p

y = p^(1/b)

(iii)

z^c = p

z = p^(1/c)

Given that y² = zx

=>(p^{\frac{1}{b})^2}=p^{\frac{1}{c}}*p^{\frac{1}{a}}

=>p^{\frac{2}{b}}=p^{\frac{1}{c}}*p^{\frac{1}{a}}

=>p^{\frac{2}{b}}=p^{\frac{1}{c}+\frac{1}{a}}

=>\boxed{\frac{2}{b}=\frac{1}{a}+\frac{1}{c}}