Question

please answer this question fast .... ques.8

Answer 1

$\huge{ \boxed {\mathfrak{Hello!!!!!}}}$



Here It Is Given That



=1 > AB=CD

=2> AD=BC



$To Prove => \: \triangle \: CBA \cong \triangle \: ADC$



PROOF:-



We need to find three reasons to prove them congruent



AB=CD (Given)



AD=BC (Given)



AC=AC (Common)



$\therefore \: \triangle \: CBA \cong \: \triangle \: ADC \:( by \: SSS \: criterian)$



Hope It Helps




$\mathbb{PLEASE \: MARK \: ME \: BRAINLIEST}$