Question

please answer this question friends ​

Answer 1

HOPE IT HELPS YOU

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Answer 2

Answer:

y^2+11y-200

Step-by-step explanation:

Distance=200km

Distance=speed×time

Let speed be x and time be y

200=x×y---------☆

If speed is 10 km/hr less, then time would be 1hr more,

x-10=y+1

x=y+10+1

x=y+11-------♡

From ☆ and ♡

200=(y+11)y

200=y^2+11y

y^2+11y-200=0