Math, asked by viveknk9458, 1 year ago

If 3 numbersare in the ratio of 1:2:3 and half of its sum is 18

Answers

Answered by aMaX728
0
Hey mate
Here is your answer :--

Let the common multiple be x

1st no. = x
2nd no. = 2x
3rd no. = 3x

Given condition is :-

x+2x+3x/2 = 18
x+2x+3x = 18 × 2
6x = 36
x = 36/ 6
x = 6

Numbers are
x= 6
2x = 2×6 = 12
3x = 3×6 = 18

Hope this help you mate
Answered by btejaswini2003
0

Answer:

Hello , here is the answer for your question :

let the numbers be x,2x,3x

Given , 1/2 ( x + 2x + 3x ) = 18

then , x+2x+3x= 36

6x = 36

x= 6

then , 2x = 12 and 3x = 18

∴ 6,12,18 ARE THE NUMBERS

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