Math, asked by ScholarPiyush, 1 year ago

please can anyone help me to solve this question its urgent!​

Attachments:

sohil88: sin2a/cosa+cosa. (sin2a+cos2a)/cosa. 1/cosa= seca

Answers

Answered by kunal0912
0

Let theta = x

so, LHS =  sin^2 x /cosx + cos x  

             = 1 - cos^2 x /cos x + cos x

             = 1 - cos^2 x + cos^2 x/cos x = 1/cos x = sec x = RHS

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