please can anyone help me to solve this question its urgent!
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sin2a/cosa+cosa. (sin2a+cos2a)/cosa. 1/cosa= seca
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Let theta = x
so, LHS = sin^2 x /cosx + cos x
= 1 - cos^2 x /cos x + cos x
= 1 - cos^2 x + cos^2 x/cos x = 1/cos x = sec x = RHS
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