Please differentiate log 10x
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Another common approach is to use the change of base formula, which says that:
log
a
(
b
)
=
ln
(
b
)
ln
(
a
)
From change of base we have
log
10
(
x
)
=
log
10
(
x
)
=
ln
(
x
)
ln
(
10
)
.
This we can differentiate as long as we remember that
1
ln
(
10
)
is just a constant multipler.
Doing the problem this way gives a result of
y
'
=
1
ln
(
10
)
⋅
1
x
.
gauravgoswami207:
sorry dude I didn't get it
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