Please do sum no. 4 of sixth part
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Step-by-step explanation:
x = (1+i)/2
or,
x² = {1+(-1)+2i}/2=i
so,
x⁴ = i² = -1
x⁶ = i³ = -1√-1
so,
x⁶+x⁴+x²+1
=-1√-1+(-1)+√-1+1
= -1√-1+√-1 = 0
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