Question

please explain me. if u can

Answer 1

your answer will be 64 ...because here the order of the matrix is 2*3 so in the given matrix there must be 6 elements and each of these 6 elements can be either 1 or-1.....so we can be filled each of the 6 elements in two ways. Therefore the number of possible matrices =2^6=64...thank you..

Answer 2

Give matrix is of order 2×3

Let A be a 2×3 matrix ...
$\binom{a _{11} \: \: a _{12} \: \: a _{13}}{ a _{21} \: \: a _{22} \: \: a _{23} }$
Total number of elements = 2×3 = 6

We have to form matrices by only using {-1,1}

$We \: have \: six \: places ... so \: we \: can \: use \: 2 \: elements \\ on \: each \: place \: hence \: total \: number \: of \: possible \: matrices \: are \: {2}^{6} = > 64$
Hence Option (d) is correct !