Question

please explain the question fully

A particle starts from rest with uniform acceleration a its velocity after n second is V the displacement of the body in the last 2 seconds is

Answer 1

we know the formula distance travelled in nth second=u+a/2(2n-1)
=a/2(2n-1)
and so the distance travelled in (n-1)the second=a/2{2(n-1)-1}
=a/2(2n-2-1)
=a/2(2n-3)
so the distance travelled in last two seconds=distance travelled in last second+distance travelled in second last second
=a/2(2n-1)+a/2(2n-3)
=a/2{2n-1+2n-3)
=a/2(4n-4)
=a/2×2(2n-2)
=a(2n-2)
answer can be expressed in other variables also plzz say me the options