Math, asked by tiaragarg, 1 year ago

Please find the values of x,y and z.

Attachments:

mohammadaliamgo: X=50°

mohammadaliamgo: Z=50°

mohammadaliamgo: Y=50°

tiaragarg: Wrong

Answers

Answered by SejalShirat

Value of x=180=130+x

x=50°

z=50 (Oppo. angle of parallelogram)
Y=50°

mohammadaliamgo: Y?

SejalShirat: sry but am unsuccessful in finding

SejalShirat: 'y'

SejalShirat: Am unable

mohammadaliamgo: Well hope I help

tiaragarg: Yes u hv helped way much better than her.......

Answered by mohammadaliamgo

In triangle BCE

angle bce=40

Angle ceb=90

Therefore,by angle sum property

X=50

Z=50 (opposite angles of parallelogram are equal)

AD||BC and DC is a transversal

Therefore,

Z+angle BCD=180

So angle BCD =130

We know BCE=40

And by angle sum property

FCD=40

THEREFORE,

angle y=130-40-40

Or y=130-80

Y=50

Previous Question

Next Question