Question

Please give correct answer
Irrelevant answers will be reported​

Answer 1

Answer:

1. -5a²bc,11ab,13abc

first multiply 13,5=65

second mutiply 65,11=715

there are 4a , 3b,and 3c so that answer is 715a4b³c³

2.(p+6)(q-7)

p(q-7)+6(q-7)

pq-7p+6q-42

3.(3/4x -4/3)y (2/3x + 3/2 y)

(3/4x -4/3y) (2/3x + (3/4x -4/3)y (3/2)y

1/2 x²y+ -8/9xy +9/8xy -2y²

1/2x²y + 9/8xy²+ -8/9xy-2y²

Answer 2

Answer:

Hi dear, i am fine, how r u

Step-by-step explanation: