Question

Please give me answer

Answer 1

⭐Solution⭐

✔Given here

lim x-> 0 [ {e^(1/x ) +1}/{ e^(1/x) - 2}]

= lim x ->0 [ e^(1/x){ 1+e^(-1/x)}/e^1/x{(1-e^{-1/x)}]

= lim x->0 [ { 1+e^(-1/x)}/{1-e^(-1/x)}]

taking limit at x->0

we get,

= [ { 1+ e ^(-∞) }/{ 1-e^(-∞)}]

= (1+0)/(1-0)

= 1/1

= 1.

✏important Formula

♠ e^(-∞) = 0

✏Hopes its helps u