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⭐Solution⭐
✔Given here
lim x-> 0 [ {e^(1/x ) +1}/{ e^(1/x) - 2}]
= lim x ->0 [ e^(1/x){ 1+e^(-1/x)}/e^1/x{(1-e^{-1/x)}]
= lim x->0 [ { 1+e^(-1/x)}/{1-e^(-1/x)}]
taking limit at x->0
we get,
= [ { 1+ e ^(-∞) }/{ 1-e^(-∞)}]
= (1+0)/(1-0)
= 1/1
= 1.
✏important Formula
♠ e^(-∞) = 0
✏Hopes its helps u
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