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As the 2 resistances arein series.
Therefore the the current across them will be same and potential difference across their points will be different.
So by the given picture then potential difference with across the circuit is 12 + 6 which is equals to 18 V.
=> I = V/R
=> I = 12/6 = 6/R. [Current is same]
=> R = 3ohm.
Reading of Ammeter will be (I) = 2A.
Hope this will help you.
If you like my answer
Please mark it as brainliest
And
Be my follower if possible.
Therefore the the current across them will be same and potential difference across their points will be different.
So by the given picture then potential difference with across the circuit is 12 + 6 which is equals to 18 V.
=> I = V/R
=> I = 12/6 = 6/R. [Current is same]
=> R = 3ohm.
Reading of Ammeter will be (I) = 2A.
Hope this will help you.
If you like my answer
Please mark it as brainliest
And
Be my follower if possible.
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