Question

please give me answer fast 5 please​

Answer 1

Answer:

Step-by-step explanation:

Area left uncovered will be

Area of square- Area of both semi circles

Radius is given

So applying area of square formula=side^2

we get 28^2=784

For semicircle area= pi *diameter^2/8

so area= 3.14*28^2/8=307.72

Now for uncovered area= 784-2(307.72)=168.56

Answered by gauthmath

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Answer 2

Given :

• Side of Square = 28 m.
• Two semi-circular grass-covered postions are to be made on two of its opposite sides.

To find :

• how much area will be left uncovered?

Solution :

⇒ Let's find the Area of Square.

$\sf \longrightarrow Area \: of \: Square = s \times s$

$\sf \longrightarrow Area \: of \: Square = 28 \times 28$

$\sf \longrightarrow Area \: of \: Square = 784$

$\sf \longrightarrow Area \: of \: Square = 784 \: m^2$

⇒ Let's find the Area of the Semi-Circle.

• Here, we have to take the side of the square as the diameter of the semi-circle.

Diameter = radius × 2

Radius = diameter/2

= 28/2

= 14 cm

$\sf \longrightarrow Area \: of \: Semi-Circle = \dfrac{1}{2} ( \pi r^2 )$

$\sf \longrightarrow Area \: of \: Semi-Circle = \dfrac{1}{2} \times ( \dfrac{22}{7} \times 14^2 )$

$\sf \longrightarrow Area \: of \: Semi-Circle = \dfrac{1}{2} \times ( \dfrac{22}{7} \times 196 )$

$\sf \longrightarrow Area \: of \: Semi-Circle = \dfrac{1}{2} \times ( \dfrac{22 \times 196}{7} )$

$\sf \longrightarrow Area \: of \: Semi-Circle = \dfrac{1}{2} \times ( \dfrac{4312}{7} )$

$\sf \longrightarrow Area \: of \: Semi-Circle = \dfrac{1 \times 4312}{2 \times 7}$

$\sf \longrightarrow Area \: of \: Semi-Circle = \dfrac{4312}{14}$

$\sf \longrightarrow Area \: of \: Semi-Circle = 308 \: m^2$

→ Area of 2 Semi-Circle = 308 × 2

→ 616 m²

⇒ Now, let's find how much area will be left.

→ Area = Area of Square - Area of 2 Semi-Circles

→ Area = 784 - 616

→ Area = 168 m²

• Therefore, 168 m² area will be uncovered.