Question

please give me solution its urgent tomorrow Is my board exam ​

Answer 1

In triangle ACB,

angle CAB = 30° (given)

angle ACB will be equal to 90° ( angle is 90° in a semicircle)

now,using angle sum of triangle property

90° + 30°+ angle ABC = 180°

120°+ angle ABC= 180°

angle ABC = 180° - 120° = 60°

by using exterior angle property,,,

angle PCA= angle CAB + angle ABC

angle PCA= 30° +60° = 90°

so,,angle PCA will be equal to 90°