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Mark as brainliest pls...
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LovableLiana:
Can you answer question no 29
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Hi friend,
Perimeter of shaded region= AB+ PB+ arc length AP=___(1)
Arc length AP=θ/360 X 2πr= πθr/180______(2)
In right triangle ΔOAB,
tanθ=AB/r=>AB=rtanθ______(3)
secθ=OB/r=>OB=rsecθ
OB=OP+PB
∴rsecθ=r+PB
∴PB=rsecθ-r____(4)
Substitute (2),(3)and(4) in (1) we get,
Perimeter of shaded region =AB+PB+arc length AP
=rtanθ+rsecθ-r+ πθr/180
=r[tanθ+secθ+πθ/180 -1]
_____________________________________________________________
Perimeter of shaded region= AB+ PB+ arc length AP=___(1)
Arc length AP=θ/360 X 2πr= πθr/180______(2)
In right triangle ΔOAB,
tanθ=AB/r=>AB=rtanθ______(3)
secθ=OB/r=>OB=rsecθ
OB=OP+PB
∴rsecθ=r+PB
∴PB=rsecθ-r____(4)
Substitute (2),(3)and(4) in (1) we get,
Perimeter of shaded region =AB+PB+arc length AP
=rtanθ+rsecθ-r+ πθr/180
=r[tanθ+secθ+πθ/180 -1]
_____________________________________________________________
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