Question

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Answer 1

Answer:

Hey dear..!

Your answer..!!

The heat of combustion at constant volume is given to be -5133 KJ/mol.

Therefore, qv=-5133 kJ/mol.

The balanced equation of combustion of naphthalene is:

C10H8 + 12O2 -----> 10CO2 + 4H2O

Here, the number of gaseous moles on the products side= 10 (10 moles of CO2)

And, the number of gaseous moles on the reactants side= 12(12 moles of O2)

Hence, the change in number of gaseous moles,

Δn = 10 - 12 = -2

The relation between qp and qv is:qp = qv + ΔnRT

Substituting the values given,

qp = -5133*103 + (-2*8.314*298)=>

qp= -5137955.144 Answer

JAI HIND.

TAKE CARE..

Answer 2

Answer:

Explanation:

The heat of combustion at constant volume is given to be -5133 KJ/mol

.Therefore, qv=-5133 kJ/mol.

The balanced equation of combustion of naphthalene is:C10H8 + 12O2 -----> 10CO2 + 4H​2O

Here,

the number of gaseous moles on the products side= 10 (10 moles of CO2)And,

the number of gaseous moles on the reactants side= 12(12 moles of O2)

Hence, the change in number of gaseous moles,

Δn = 10 - 12 = -2The relation between qp and qv is:qp = qv + ΔnRTSubstituting the values given,

qp = -5133*103 + (-2*8.314*298)=> qp= -5137955.144 J/mol

#aakashian...XD

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