Math, asked by Bhagabatibehera44196, 1 month ago

please help fast urgent

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Answered by ExploringMathematics
0

\rm{(5/7)^3\times(5/7)^{-6}=(5/7)^{2x+3}}

\longrightarrow\rm{(5/7)^{3+(-6)}=(5/7)^{2x+3}\quad...\:Since\:a^m+a^n=a^{m+n}}

\longrightarrow\rm{3+(-6)=2x+3\quad...\:Comparing\: the\: Bases}

\longrightarrow\rm{3-6=2x+3}\longrightarrow\rm{-3=2x+3}

\longrightarrow\rm{2x=-3-3=-6}

\longrightarrow\rm{x=-6/2=-3}

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