Question

please help me fast.....​

Answer 1

$\mathrm\green{∠PQH\:=\:55°}$

∠QHP = 35° ➜ Alternate Angles of a transversal are Equal

As ∠EGB = 35°

∠PHQ = 35°

In ∆QHP ∠Q=x° ∠H=35° ∠P=90°

According to Angle Sum Property of a Triangle all the angles in a ∆ should be equal .

So, x + 35 + 90 = 180

x + 125 = 180

∴x = 180 - 125 = 55

$\green\large\boxed{∠PQH=55°}$

Answer 2

Step-by-step explanation:

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QHP = 35° ➜ Alternate Angles of a transversal are Equal

As ∠EGB = 35°

∠PHQ = 35°

In ∆QHP ∠Q=x° ∠H=35° ∠P=90°

According to Angle Sum Property of a Triangle all the angles in a ∆ should be equal .

So, x + 35 + 90 = 180

x + 125 = 180

∴x = 180 - 125 = 55

$\red\large\boxed{∠PQH=55°}$

∠PQH=55°

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