Question

please help me fast it is urgent

Answer 1

I think in this question you have to find A , B , C
Now Look this question AB × BA = 5CB
means that when you multiply BA with B it gives unit digit B ( I m telling unit digit not the whole number) BA×B = XYB ( here X and Y can be any digit) Now see when multiplying B×A we are getting NB(N can be any number). So we can A must be 1. Now we got 1B×B1 = 5CB. we can understand by seeing the equation that and a number when multiplied by inversing it digit we get 5CB.
To find
B can be from 0 to 9
now let's choose B = 5
15×51 = 765
But no. start with 5 (5CB) so the number must be less than 599
B<5
let be 4
14×41 =574
We finally got the required no.
A= 1 , B = 4 , C = 7


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Answer 2

Answer:

A=1 B=4 C=7

Step-by-step explanation:

Here value of A must be 1

Since,B*A=British

For ex-2×1=2,3*1=3 and so on.

If A=any other number it's value of B changes.for ex-2×2=4 where value of b differs i.e 2 and 4.thus a=1

Now,1b*b1=5cb

The value of this=5cb=b^2+1=c

Now b must be 0-9 and the total no. Should be less than 599

Let the value of b=4

So 14*41=574 which is less than 599

So we got a=1 b=4 and c=7

Hope it helps:)