please help me i will mark as brainlist
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Given the length of the room = 5m.
Given the breadth of the room = 4m.
Given the height of the room = 3m.
Now,
Area to be white-washed = 2lh + 2bh + l * b
= 2(5 * 3) + 2(4 * 3) + 5 * 4
= 30 + 24 + 20
= 74m^2.
Given the cost of white-washing per m^2 = 7.50.
Therefore, the cost of white-washing 74m^2 = 74 * 7.50
= 555.
Therefore the total cost of white-washing = 555.
Hope this helps!
Given the breadth of the room = 4m.
Given the height of the room = 3m.
Now,
Area to be white-washed = 2lh + 2bh + l * b
= 2(5 * 3) + 2(4 * 3) + 5 * 4
= 30 + 24 + 20
= 74m^2.
Given the cost of white-washing per m^2 = 7.50.
Therefore, the cost of white-washing 74m^2 = 74 * 7.50
= 555.
Therefore the total cost of white-washing = 555.
Hope this helps!
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about alloys
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