Question

please help me in this question

Answer 1

Hi Mate!!!

ABC + BCA + BAC = 180 ( Angle sum property)


40° + 15° + BCA = 180°

BCA = 125°

BCA + ACD = 180 ( because sum of these two angles makes a straight line)

ACD = 55°


In Trangle ECD

ECD + CED + EDC = 180

CED = 180 - 107

CED = 73°

AED + CED = 180°

AED = 180-73 = 107°


Have a great future ahead

Answer 2

$< acd = < bac + < abc \\ (by \: exterior \: angle \: sum \: of \: property) \\ < acd = 15 + 40 \\ < acd = 55 degree \\ \\ in \: triangle \: ecd \\ < ecd + < edc + < ced = 180 \: degree \\ 55 + 52 = 180 \: degrees \\ 107 + < ced = 180 \: degrees \\ < ced \: = 180 - 107 \\ < ced \: = 73 \: degree \\ \\ < aed + < ced = 180 \: degree \\ (linear \: pair \: ) \\ < aed + 73 = 180 \: degree \\ < aed = 180 - 73 \\ < aed = 107 \: degree \: \\ answer \: is \: clear \: < acd = 55 \: degree \: \\ < aed = 107 \: degree$