please help me it is so hard
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3)-
if the sum of digit's of any number is divisible by 9 then the whole number is also divisible by 9 now here sum of digit's of the number=4+5+6+p+8=23+p,. so now to make it divisible by 9 we have to take p as 4 so that sum of the digit's became 27 which is exactly divisible by 9,
so the value of p will be 4
4)-
unit place digit will be 8,
5)-
unit place digit will be 3,
6)-
unit place digit will be 6,
7)-
unit place digit will be 4
if the sum of digit's of any number is divisible by 9 then the whole number is also divisible by 9 now here sum of digit's of the number=4+5+6+p+8=23+p,. so now to make it divisible by 9 we have to take p as 4 so that sum of the digit's became 27 which is exactly divisible by 9,
so the value of p will be 4
4)-
unit place digit will be 8,
5)-
unit place digit will be 3,
6)-
unit place digit will be 6,
7)-
unit place digit will be 4
primeministero648:
I will send you one crore
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