Math, asked by gdgxjfjfkh, 1 year ago

please help me my problem is so hard

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Answered by digi18
0
1). (1 + secA) / secA = sin^2A / (1 - cosA)

1/secA + secA/secA = (1 - cos^2A) / (1 - cosA)

cosA + 1 = (1+ cosA)(1 - cosA) / (1 - cosA)

1 + cosA = 1 + cosA

Hence proved


3). (secA - 1) / (secA + 1) = (1 - cosA) / (1+ cosA)

Take LHS

(1 /cosA - 1) / (1/cosA + 1)

{ (1 - cosA) / cosA} / {( 1 + cosA) / cosA}

(1 - cosA) / (1 + cosA)

LHS = RHS

Hence proved


Thanks

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