Question

Please help me out with this question:
5(y+1)=25​

Answer 1

Answer:

25^x = 5^y-1

=> 5^2x = 5^y-1

Therefore, 2x=y-1

=> x=(y-1)/2

32^y= 4*8^x

=> 2^5y=2^(3x+2)

Therefore, 5y=3x+2=3(y-1)/2 + 2 (substitution)=(3y-3+4)/2=(3y+1)/2

=> 10y = 3y + 1

=> y=1/7

x=(y-1)/2 = -6/14 = -3/7

Answer 2

Answer:

5( y+1) = 25

y+1 = 25/5

y = 5-1

y = 4