Question

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Answer 1

Answer:

here is u r answer..

Step-by-step explanation:

i]  [log[1+2+3]=log1+log2+log3 {add the all numbers}

log[6]=log1*2*3 ......log[6]=log[6]

so both equations are equal

ii] 2 rational numbers between 1/3 and1/6 are

1/3 multiply 2 and 1/6also *2

then we get 2/6  multiply *2 and 1/6 we get 2/12 multiply it with 1 only

then we get 4/12 and 2/12..

the rational number is 3/12...

iii] To check if three points are collinear we draw line joining any two of them and then check if third point also lie on that line.

Equation of line passing through [math](a,0)[/math] and [math](0,b)[/math] is [math]\frac{x}{a} + \frac{y}{b} = 1[/math]

because it has [math]a[/math] intercept on X-axis and [math]b[/math] intercept on Y-axis.

Let’s check if (1,1) lies on this line, by substituting the value of coordinated of this point in the line,

[math]\frac{1}{a} + \frac{1}{b} = 1[/math] this is given to be true, as per the problem.

So, [math](1,1)[/math] lies on [math]\frac{x}{a} + \frac{y}{b} = 1[/math]

This means [math](a, 0),[/math] [math](0, b)[/math] and [math](1,1)[/math] are collinear

if any wrongs i am sorry..

THANK YOU