Question

please help me to find the answer - an organic compound contains C 12 times that of H and O 2/9 th times that of C. Find its empirical formula. Please help me​

Answer 1

Answer:

Molecular Formula -

The molecular formula shows the exact number of different types of atoms present in a molecule of a compound.

- wherein

For glucose, empirical formula is CH2O .its molar mass is 180 gram.

n = molar mass/empirical formula mass = 180/30=6

Hence molecular formula= C6H12O6

 

Molecular mass = 2\times 73 =146

 

C = \frac{\%}{100}\times \frac{Molecular \;mass}{Atomic \;mass} = \frac{49.3}{100}\times \frac{146}{12} = 6

H = \frac{\%}{100}\times \frac{Molecular \;mass}{Atomic \;mass} = \frac{6.84}{100}\times \frac{146}{1} = 10

O = \frac{\%}{100}\times \frac{Molecular \;mass}{Atomic \;mass} = \frac{43.86}{100}\times \frac{146}{16} = 4

Molecular Formula = C6H10O4

Molecular mass = 12\times 6 + 10\times 1 + 16\times 4 = 146

C6H10O4