Question

Please help me to solve this question

Answer 1

Given PC = 20cm, QC = 20cm, PQ = 14cm.

In triangle ACD,

= > AC^2 = AD^2 + DC^2

= > 44^2 = AD^2 + AD^2[AB = BC = CD = DA]

= > 44^2 = 2AD^2

= > AD^2 = 22 * 44

= > AD^2 = 968

$= > AD = 22\sqrt{2}cm$

Now,

We know that Area of square = s^2

$= > 22\sqrt{2} * 22\sqrt{2}$

968cm^2.

Now,

Area of red portion = 968/4 = 242cm^2.

Area of green portion = 968/4 = 242cm^2.

Area of yellow portion = 968/2 = 484cm^2.

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In triangle PCQ,

s = 20 + 20 + 14/2 = 27cm.

Area of triangle PCQ =

$= > \sqrt{(27)(27 - 20)(27 - 20)(27 - 14)}$

$= > \sqrt{27 * 7 * 7 * 13}$

$= > \sqrt{17199}$

= > 131.1cm^2.

Total green portion = 242 + 131.1 = 373.1cm^2.

Therefore,

Area of green shaded region = 373.1cm^2.

Area of red shaded region = 242cm^2

Area of yellow shaded region = 484cm^2.

Hope this helps!

Answer 2

Answer:

A student repeats the experiment to determine the boiling point of pure water with the same

set up by adding some salt to the distilled water. Will the boiling point so determined be same or different

from the boiling point of pure water? Give reason. (with proper explanation only )