Question

please help me with this.
as soon as possible​

Answer 1

Let the five consecutive positive integers be :

a-2d,a-d,a,a+d, and a+2d since sum of these numbers is 90 as given =>

(a-2d)+(a-d)+(a)+(a+d)+(a+2d) =90

=> 5a = 90

=> a =18

now since they are consecutive the difference between two consecutive positive integers should be 1 =>

(a) - (a-d) =1

=> d =1

since our five consecutive integers were :

16,17,18,19,20 whose sum is 90 now next consecutive numbers are :

21,22,23,24,25 whose sum is :

21+22+23+24+25 = 115.

since ration of 90 to 115 is the required ration =>

90 : 115

=18 : 23 [ANSWER]

HOPE THIS HELPS YOU

Answer 2

Answer:

6:7

$x + x + 1 + x + 2 + x + 3 + x + 4 = 90 \\ \\ 5x = 80 \\ \\ x = 16 \\ \\ so \: \: the \: \: numbers \: \: are \: \: (16 - 21) \\ \\ sum \: of \: this \: numbers(16 - 21) = 90 \\ \\ sum \: of \: next \: five \: numbers \: = \: 105 \\ \\ \\ ratio \: = \: 105 : 90 \\ \\ 6 : 7$