Question

please help me with this math..Step-by-Step explanation needed..please​

Answer 1

1. AOC = AOB + BOC

180° = 50° + BOC

BOC = 180°-50°

BOC = 130°

2. EOC = EOD + COD

90° = EOD + 25°

EOD = 90° - 25°

EOD = 65°

3. BOD = COD + BOC

BOD = 25° + 130°

BOD = 155°

4. BOD = AOB + AOE + EOD

BOD = 50° + 90° + 65°

BOD = 205°

5. COE = BOC + AOB + AOE

COE = 130° + 50° + 90°

COE = 270°

Answer 2

1)given AOB=50,AOE=90,COD=25

now because AOC is a straight line so

AOC=180

or AOB+BOC=180

or 50 +BOC =180

or BOC=180- 50

so BOC=130

2)because EO is perpendicular to OC

so EOC =90

or COD +EOD =90

or 25+ EOD=90

or EOD=90-25

so EOD=65

3) obtuse angle BOD= BOC+COD

BOD= 130+25=155

4) reflex angle BOD=AOB+AOE+EOD

BOD=50 +90 +65

BOD=205

5)reflex angle COE=BOC+AOB+AOE

COE= 130+50+90

COE=270