Question

please help me with this..more clearly

Answer 1

hey take common from them and then it will reduce to 1/2
pls mark brainliest

Answer 2

$\textbf {Hey there, here is the solution.}$

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$\dfrac{2^{30} + 2^{29} + 2^{28}}{2^{31} + 2^{30} + 2^{29}}$

.

Take out common factors from the numerator an denominator:

$= \dfrac{2^{28}(2^2 + 2 + 1 )}{2^{29}(2^2 + 2^ + 1)}$

.

Simplify the factors:

Note that 2^{28} ÷ 2^{29} = 2^{28 - 29} = 2^{-1} = 1/2:

$= \dfrac{(2^2 + 2 + 1 )}{2(2^2 + 2 + 1)}$

.

Evaluate the exponents:

Note that 2^2 = 4

$= \dfrac{(4 + 2 + 1 )}{2(4 + 2 + 1)}$

.

Combine the like terms:

$= \dfrac{(7 )}{2(7)}$

.

Simplify:

$= \dfrac{1 }{2}$

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$\textbf {Cheers}$