Math, asked by AlejandroicDude, 1 year ago

please help me with this problem.
please also mention the steps.

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Answers

Answered by Anonymous
3
divide numerator and denominator by sinA
and we get
cotA+cosecA-1 \div cotA - cosecA + 1
put the value of 1

cotA+cosecA-(cosec²A-cot²A)/ cotA -cosecA + 1

=> cotA+cosecA-(cosecA-cotA)(cosecA+cotA/cotA-cosecA+1
taking cotA+cosec A as common
=>(cotA+cosecA)(cotA-cosecA+1)/(cotA-cosecA+1
=>cotA+cosecA
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