Question

Please help me with this question ​

Answer 1

Answer:

$\alpha =\frac{2\pi}{3} \\sin\alpha -cos\alpha =sin\frac{2\pi}{3} -cos\frac{2\pi}{3} \\sin\frac{2\pi}{3} =sin 60=\frac{\sqrt{3} }{2}$

$\\cos\frac{2\pi}{3} =cos 60=\frac{{1} }{2}$

$\\sin\frac{2\pi}{3} -cos \frac{{2\pi } }{3}=\frac{\sqrt{3} -1}{2}$

Answer 2

$\huge\underline\mathfrak{\pink{AnS wEr :- }}$